Spring MVC Submit Form jQuery

Spring MVC Submit Form jQuery

In this tutorial you will see how to submit Spring MVC application form data using jQuery. Please follow steps below:

  • Download and unzip code and import as maven project into eclipse.
  • Project structure:

Spring MVC Submit Form jQuery

  • SubmitForm.jsp:
<%@ taglib prefix="form" uri="http://www.springframework.org/tags/form"%>
<%@ page language="java" contentType="text/html; charset=ISO-8859-1" pageEncoding="ISO-8859-1"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
<title>Spring MVC submit form AJAX JQuery</title>
<script src="http:////code.jquery.com/jquery-1.10.2.js"></script>
<script type="text/javascript">
	
	$(document).ready(function() {

		$('#submitId').click(function() {
			$( "#submitForm" ).submit();
		});
	});
</script>
</head>
<body>
<form:form commandName="user" action="submitForm.web" method="post" id="submitForm">     

	    <fieldset style="width: 300px;">
	        <legend>User details</legend>
	        <ol>
	            <li>
	                <p><label for=name>Name</label>
	                <form:input path="name"  type="text" placeholder="First and last name" /></p>
	            </li>
	            <li>
	                <p><label for=name>Date</label>&nbsp;&nbsp;
	            	<form:input path="dob" type="date" required="true"/></p>
	            </li>
	            <li>
	                <p><label for=email>Email</label>
	                <form:input path="email" type="text" required="true" /></p>
	            </li>
	            <li>
	                <p><label for=phone>Phone</label>
	                <form:input path="phone" type="text" required="true" /></p>
	            </li>
	         </ol>
	    </fieldset>

		<fieldset style="width: 300px;">
			<input id="submitId" type="button" value="Submit Form">
		</fieldset>

	</form:form> 		
        
</body>
</html>
  • SpringMVCController.java:
package com.javahonk.controller;

import org.apache.log4j.Logger;
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.ModelAttribute;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.servlet.ModelAndView;


@Controller
public class SpringMVCController {
	
	private static final Logger logger = Logger.getLogger(SpringMVCController.class);
	
	@RequestMapping(value = "/helloWorld.web", method = RequestMethod.GET)
	public ModelAndView printWelcome(@ModelAttribute("user") Users user) {

		ModelAndView mav = new ModelAndView("SubmitForm");
		mav.addObject("message", "Hello World!!!");
		return mav;

	}

	@RequestMapping(value="/submitForm.web", method = RequestMethod.POST)
    public ModelAndView  submittedFromData(@ModelAttribute("user") Users user) {	
		logger.debug("submitted FromData mehtod called");
		ModelAndView mav = new ModelAndView("SubmitForm");
		return mav;
	}	
	
}
  • Application output:

Spring MVC Submit Form jQuery Spring MVC Submit Form jQuery

  • For more information about jQuery form submit please use this link

download  Download Project:  SpringMVCAJAXFormSubmit

2 thoughts on “Spring MVC Submit Form jQuery”
  1. I used this but it is not working with spring 3. when i am using @ModelAttribute then only it’s calling Controller method but when i am using @RequestBody then it’s not working
    so what i should do?

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